Question

The digit in the ten's place of a two-digit number is three times that in the one's place. If the digits are
reversed the new number will be 36 less than the original number. Find the number.​

Answer 1

Step-by-step explanation:

Let the one's digit be y and tens digit be x,

Number = 10x + y

Then,x=3y⋯(i)

Reversed number = 10y + x

A.t.Q :- (10x+y)−(10y+x)=36 Put x = 3y in eq. (i)

⇒9x−9y=36

⇒x−y=4⋯(ii)

⇒3y−y=4

∴2y=4 x=3y ∴x=6

y=2

∴ Number = 62

Answer 2

let the digit on once place be x and on tenths place be y.

thus, 3y = x -------1.)

10y + x = 10x + y -36

9x - 9y = 36

x- y = 4---------2.)

now put the value of y in 1.) to 2.)

implies that,

3y - y = 4

y=2

thus, x = 3y = 3 × 2 = 6

thus, x=6 and y=2

hope it helps you.

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