Question

the digit in the tens place is 1 more than twice the digit in the units place.if the digits are reversed,the difference between the two numbers is 27.Find the original number.

Answer 1

Answer:

Let the digit at units place be x.

Then the digit at tens place would be 2x + 1.

Number = 10(2x + 1) + 1(x) = 20x + 10 + x = 21x + 10

Reversed Number = 10(x) + 1(2x + 1) = 10x + 2x + 1 = 12x + 1

Difference = 27

27 = 21x + 10 - (12x + 1)

27 = 21x + 10 - 12x - 1

27 = 9x + 9

18 = 9x

x = 2

Units Place = x = 2

Tens Place = 2x + 1 = 4 + 1 = 5

Original Number = 10(5)+ 1(2) = 50 + 2 = 52

Step-by-step explanation:

Answer 2

Answer:

52

Step-by-step explanation:

Let unit in units place be x

so, unit in tens place = 2x+1

so, no. = (2x+1)*10+(x*1)

so, reversed no. = 10x+ 2x+1

A/Q,

{(2x+1)*10+(x*1)}-{10x+2x+1}=27

=> {20x+10+x}-{12x+1}=27

=> 21x+10-12x-1=27

=> 9x= 27-10+1

=> x=18/9

=>.x=2

Therefore, the no. is (2x+1)*10+(x+1)

= 52