the digit in the tens place of a 2 digit number is 6 more than the digit in the unit place. the sum of the number and the number obtained by reversing the digits is 66. find the number.
Answers
Answered by
40
Answer:
60
Step-by-step explanation:
Let the unit's place be x
Ten's place = x+6
Number formed = 10(x+6) + x
= 10x + 60 + x
= 11x+60
Reversing the number = 10x+ x+6
= 11x+6
Now sum of these numbers = 66
11x+60 + 11x+6 = 66
22x+66=66
22x=0
x = 0
x+6 = 6
Number formed = 60
Reversed number = 06
Two digit required number = 60
Answered by
9
Answer:
Step-by-step explanation:
#BAL #best quality
in the given question it is clear that the number obtained by adding number and its reversing is 66
so we can easily verify
either we will get 24 ,42 or 33,33 or 60,06
so it is obvious that tens place is 6 more than unit place
so answer is 60
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