The digit in the tens place of a two-digit no. is
three times that in the units place. If the digit
reversed the new mo. will be 36 less thom the
Briginal mo.. Find the original mo. check your
your
Solution
Answers
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Answer:
Let the one's digit be y and tens digit be x,
Number = 10x + y
Then,x=3y⋯(i)
Reversed number = 10y + x
A.t.Q :- (10x+y)−(10y+x)=36 Put x = 3y in eq. (i)
⇒9x−9y=36
⇒x−y=4⋯(ii)
⇒3y−y=4
∴2y=4 x=3y ∴x=6
y=2
∴ Number = 62
Step-by-step explanation:
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Given :
- The digit in the tens place of a two-digit no. is three times that in the units place.
- If the digit is reversed, the new no. will be 36 less than the original no.
To find :
- The number.
Solution :
Let the one's digit be y and tens digit be x,
Then,
- Number = 10x + y
As the digit in the tens place of a two-digit no. is three times that in the units place,
→x=3y⋯(i)
And,
- Reversed number = 10y + x
According to question,
→(10x+y)−(10y+x)=36
Putting x = 3y
→9x−9y=36
→x−y=4⋯(ii)
→3y−y=4
→2y=4
→y=2
And we have,
→3y = x
→3(2) = x
→x = 6
Hence, the Number is 62.
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