Math, asked by anshthakur090, 2 months ago

The digit in the tens place of a two-digit no. is
three times that in the units place. If the digit
reversed the new mo. will be 36 less thom the
Briginal mo.. Find the original mo. check your
your
Solution​

Answers

Answered by rupaliaery
0

Answer:

Let the one's digit be y and tens digit be x,

Number = 10x + y

Then,x=3y⋯(i)

Reversed number = 10y + x

A.t.Q :- (10x+y)−(10y+x)=36 Put x = 3y in eq. (i)

⇒9x−9y=36

⇒x−y=4⋯(ii)

⇒3y−y=4

∴2y=4 x=3y ∴x=6

y=2

∴ Number = 62

Step-by-step explanation:

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Answered by EnchantedGirl
14

Given :

  • The digit in the tens place of a two-digit no. is  three times that in the units place.
  • If the digit  is reversed, the new no. will be 36 less than the  original no.

To find :

  • The number.

Solution :

Let the one's digit be y and tens digit be x,

Then,

  • Number = 10x + y

As the digit in the tens place of a two-digit no. is  three times that in the units place,

→x=3y⋯(i)

And,

  • Reversed number = 10y + x

According to question,

→(10x+y)−(10y+x)=36

Putting x = 3y  

→9x−9y=36

→x−y=4⋯(ii)

→3y−y=4

→2y=4  

→y=2

And we have,

→3y = x

→3(2) = x

x = 6

Hence, the Number is 62.

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