Question

the digit in the tens place of a two digit number is 1 more than the digit in the ones place the difference between the two number and the number we get after interchanging the digit is equal to the sum of two digit

Answer 1

let x = the 10's digit

let y = the units

then

10x+y = the number

:

Write an equation for each statement:

:

" the digit at the tens place of a two digit number is three times the digit at ones place."

x = 3y

:

 

"The sum of this number and the number formed by reversing its digit is 88,"

(10x + y) + (10y + x) = 88

10x + x + 10y + y = 88

11x + 11y = 88

simplify, divide by 11

x + y = 8

:

You should be able to do it now. (Replace x with 3y)