Question

The digit in the tens place of a two digit number is 3 more than the digit in the units place. Let the digit at units place be b. Then the number is​

Answer 1

$\bf\underbrace{ANSWER}$

⇒11b=30

$\bf\underbrace{STEP \ BY \ STEP \ EXPLANATION}$

From the question it is given that,

Let, the digit at units place be "b"

The digit in the tens place of a two digit number is 3 more that the digit in the units place =3+b

So, the number = 10(3+b)+b

⇒30+10b+b

⇒30+11b

     (or)

⇒11b+30

∴The number is "11b+30"

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