Question

The digit in the tens place of a two digit number is 3 more than the digit in the unit place. Let the digit at units place be b. Then the number is

Answer 1

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hey Mate!!!!}}}$

Let the number at the unit place be b

So, the number at the tens place will be
= 10x(b+ 3)

Then the number is
= 10(b + 3)+b
= 10b+30 +b
= 11b + 30

If, b =1

Then

11(1)+30
=41

$\huge\blue{HoPe....iT....HeLpS....YoU...}$

Answer 2

Answer:

11b+30

Step-by-step explanation:

Digit in unit’s place is b (given).

Digits in ten’s place is 3 more than digit in unit’s place.

So digit in ten’s place is (b+3)

Two digit number = 10* digit in ten’s place + digit in unit’s place.

= 10 *(b+3) + b

= 11*b +30

Hence the answer is 11b+30