Question

The digit in the tens place of a two digit number is 3 more than the digit in
the units place. Let the digit at units place be x. Then the number is:
A.10x + 30
A.10x + 30
B.11x + 30
B.11x + 30
C.11x + 3
C.11x + 3
D.10x + 3
D.10x + 3

Answer 1

Given: The digit at the units place be x .

So, the digit at the team's place = x + 3.

Therefore the number = 10(x + 3 ) + x = 10x + 3 + x = 11x + 3.

So, the correct option is C.

Answer 2

Answer:11x +30

Step-by-step explanation:

Given : unit digit is x and ten digit is x +3

The number will be

10(x+3)+x

10x+30+x

11x+30

hence the required solution is b