the digit in the tens place of a two digit number is 3 times that in the units place. if the digits are reversed, the new number will be 36 less the original number. find the original number. check your solution
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let the digit in tenth place be 'x'
and ones be 'y'
(1)....
x = 3y
(2).....
10x + y = x + 10y + 36
9x - 9y = 36
---------------------------
from (1) and (2)
27y - 9y = 36
y = 2
and
x = 3 * 2 = 6
the number is 63
let the digit in tenth place be 'x'
and ones be 'y'
(1)....
x = 3y
(2).....
10x + y = x + 10y + 36
9x - 9y = 36
---------------------------
from (1) and (2)
27y - 9y = 36
y = 2
and
x = 3 * 2 = 6
the number is 63
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