Question

the digit in the tens place of a two digit number is 4 times the digit in the units place when the digits are reversed the number obtained is 27 less than the original number find the original number

Answer 1

Let the digits in the unit place is x
∴The digits in the unit place is 4x (According to the question)
Now original no is 4x×10 + x
And reversed no is 10x + 4x
Now A/q,
           14x=41x - 27
            27x = 27
           ∴x=1
Now putting the value of x=1 in original no=4x×10+x we get 4×10+1=41

Hope u got the answer.

Answer 2

let no. 10x + y
a/q X = 4y
X - 4y = 0 ...........(1)
and 10y + X = 10x + y - 27
9x - 9y = 27
X - y = 3 ...............(2)
from eq. (1) and (2)
X = 4
y = 1
required no. 10X + y = 10*4 + 1
= 41