Question

The digit in the tens place of a two digit number is 6 more than the digit in the unit place. The sum of the number and the number obtained by reversing the digit is 66. Find the number

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

let the unit place be x and the tense be y

Orignal no -> 10y + x

Reversing no -> 10x +y

A.T.Q

x + 6 = y  .............(1)

10y + x + 10x + y = 66

11x + 11y = 66

x + y = 6 ..........(2)

from 1 , x = y - 6

putting value of x in 2

y - 6 + y = 6

2y = 12

y = 6

putting  val of y in 1

x + 6 = 6

x = 0

x = 0 , y = 6

Orignal no - > 10y + x

= 10(6) + 0

=16

Answer : the no obtained is 16