The digit in the tens place of a two digit number is 6 more than the digit in the unit place. The sum of the number and the number obtained by reversing the digit is 66. Find the number
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Step-by-step explanation:
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Step-by-step explanation:
let the unit place be x and the tense be y
Orignal no -> 10y + x
Reversing no -> 10x +y
A.T.Q
x + 6 = y .............(1)
10y + x + 10x + y = 66
11x + 11y = 66
x + y = 6 ..........(2)
from 1 , x = y - 6
putting value of x in 2
y - 6 + y = 6
2y = 12
y = 6
putting val of y in 1
x + 6 = 6
x = 0
x = 0 , y = 6
Orignal no - > 10y + x
= 10(6) + 0
=16
Answer : the no obtained is 16
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