The digit in the tens place of a two digit number is 6 more than the digit in the units place.The sum of the number and the number obtained by reversing the digits is 66.Find the number (15 points)
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Answer:
60
Step-by-step explanation:
Let the unit's place be x
Ten's place = x+6
Number formed = 10(x+6) + x
= 10x + 60 + x
= 11x+60
Reversing the number = 10x+ x+6
= 11x+6
Now sum of these numbers = 66
11x+60 + 11x+6 = 66
22x+66=66
22x=0
x = 0
x+6 = 6
Number formed = 60
Reversed number = 06
Two digit required number = 60
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