Question

the digit in the tens place of a two-digit number is four times the digit in the units place. when the digits are reversed, the number obtained is 27 less than the original number. find the iriginal number

Answer 1

Hi ,

let the unit place digit = x

ten's place digit = 4x

original number = 10 × 4x + x

= 40x + x

= 41x -----( 1 )

according to the problem given,

when the digits are reversed , the number obtained is 27 less than the original number.

10x + 4x +27 = 41x

14x + 27 = 41x

27 = 41x - 14x

27 = 27x

27x = 27

x = 27 /27

x = 1

Therefore ,

original number = 41x

= 41 × 1

= 41

I hope this helps you.

:)