Question

the digit in the tens place of a two digit number is three time that in ones place if the disease are reversed the new number will be 54 less than the original number
find the number​

Answer 1

Answer:

Number is 62.

Let say ‘x' is digit on one's place so 3x is digit on tens' place

So number is 10*3x+x=31x

Now if reverse the possition of digit new number is

10*x+3x=13x

As given new number is less by 36 from old number

31x-36=13x

18x=36

x=2

So number is 10*3*2+2=62.

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