Question

the digit in the tens place of a two digit number is three times that is at the units place if the digits are reserved the new number is 36 less than the original number find the original number​

Answer 1

Answer :-

= 62

Step-by-step explanation:

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Answer 2

${\red{\underline{\textsf{\textbf{Answer : }}}}}$

The number is 62.

${\green{\underline{\textsf{\textbf{Explaination : }}}}}$

Let's assume

➩ The numbers are x(ten's digit) and y (ones digit)

Number formed :

➩ 10x + y

Reversing the digits :

➩ 10y + x

As it is told that x is 3 times y

So, x = 3y ...... (i)

According to the question,

$\sf : \implies \: (10x + y) - (10y + x) = 36 \\ \sf : \implies \: 10x + y - 10y - x = 36 \\ \sf : \implies \: 9x - 9y = 36 \\ \sf : \implies \:9( x - y) = 36 \\ \sf : \implies \: x - y = \frac{36}{9} \\ \sf : \implies \: x - y = 36 \\ { \underbrace{ \textbf{ \textsf{ From ..(i)}}}} \\ \sf : \implies \: 3y - y = 36 \\ \sf : \implies \: 2y = 36 \\ \sf : \implies \: y = \frac{4}{2} \\ \sf : \implies \: y = 2$

After solving we get :

➩ y = 2

And also,

x = 3y

x = 3*2

x = 6

Hence,

The number is :

➩ 10x + y

➩ (10*6) + (2)

➩ 60 + 2

➩ 62 ans.