Question

the digit in the tens place of a two-digit number is three times that in the ones place . if the digit are reversed ,the new number will be 36 less than the original find the number​

Answer 1

Correct Question:-

the digit in the tens place of a two-digit number is three times that in the ones place . if the digit are reversed ,the new number will be 36 less than the original find the number

Answer

62 .

Solution :

Let's take one's place = x

And tens place be 3x

Therefore, the original number will be

$= > 10 \times 3x + x = 30x + x$

We will reverse the number and then the new.no

$= > 10 \times x + 3x= 10x + 3x$

$30x + x - (10x + 3x) = 36$

$= > 31x - 10x - 3x + 36 \\ 18x = 36$

$= > x = 2$

So the original number will be

$= > 10 \times 3 \times 2 + 2 = 62$

Answer 2

Let the digit at ones place be x .

According to question , the digit at tens place is thrice the digit at ones place .

So , digit at tens place = 3x .

Hence , the two digit original number is

10 (3x) + x = 30x + x

= 31 x

When the digits are reversed ,

ones place digit = 3x and tens place digit = x

So , new two digit number becomes

10x + 3x = 13x

According to the question

Original number - new number = 36

31 x - 13x = 36

18x = 36

x = $\sf\ \frac{36}{18}$

x = 2

Hence , the original number is 31 x = 31 ×2

= 62

Verification :

The number when reversed becomes 26

62 - 26 = 36

Hence verified