The digit in the tens place of a two-digit number is three times that in the
units place. If the digits are reversed the new number will be 36 less than the
original number. Find the original number,
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Step-by-step explanation:
Let the one's digit be y and tens digit be x,
Number = 10x + y
Then,x=3y⋯(i)
Reversed number = 10y + x
A.t.Q :- (10x+y)−(10y+x)=36 Put x = 3y in eq. (i)
⇒9x−9y=36
⇒x−y=4⋯(ii)
⇒3y−y=4
∴2y=4 x=3y ∴x=6
y=2
∴ Number = 62
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