the digit in the tens place of a two digit number is three times that in ones place . if the digits are reversed the new number will be 36 less than the original number. find the number.
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Answered by
4
according to question
let, the unit digit = x then the tens digit = 3x because according to question tens digit is 3 times of unit digit.
now the number = 10(3x) + x = 31x
put it eq'n 1 now ,
reversing the original number 10(3x) + x
= 10x + 3x . 10x + 3x
= 31x -36 . 36
= 31x -13x .
next 36 = 18x .
now x = 2 .
put the value of x in eq'n 1 , 31(2)= 62
the original number obtained is 62
let, the unit digit = x then the tens digit = 3x because according to question tens digit is 3 times of unit digit.
now the number = 10(3x) + x = 31x
put it eq'n 1 now ,
reversing the original number 10(3x) + x
= 10x + 3x . 10x + 3x
= 31x -36 . 36
= 31x -13x .
next 36 = 18x .
now x = 2 .
put the value of x in eq'n 1 , 31(2)= 62
the original number obtained is 62
Answered by
2
let the dkgit at ones place be x
original no.- 10×3x+x=31x
Reversed-10×x+3x=13x
31x-36=13x
31x-13x=36
18x=36
x=2
original no. is 10×6+2=62
original no.- 10×3x+x=31x
Reversed-10×x+3x=13x
31x-36=13x
31x-13x=36
18x=36
x=2
original no. is 10×6+2=62
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