The digit in the tens place of a two-digit number is three times that in the units place. If the
digits are reversed, the new number will be 36 less than the original number. Find the
original number. Check your solution.
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Step-by-step explanation:
Let the one's digit be y and tens digit be x,
Number = 10x + y
Then,x=3y⋯(i)
Reversed number = 10y + x
A.t.Q :- (10x+y)−(10y+x)=36 Put x = 3y in eq. (i)
⇒9x−9y=36
⇒x−y=4⋯(ii)
⇒3y−y=4
∴2y=4 x=3y ∴x=6
y=2
∴ Number = 62
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