Question

The digit in the tens place of a two-digit number is three times that in the units place.

If the digits are reversed, the new number will be 54 less than the original number.

Find the original number.

Answer 1

THE ORIGINAL NUMBER IS 93

Step-by-step explanation:

Let The Digit On One's Place Be ( X ) And On The Ten's Place Be 3X

Then,

( 10 × 3X ) + X

= 30X + X

= 31X

If Reverse,

The New Number

==> ( 10 × X ) + 3X

= 10X + 3X

= 13X

We Know, New Number Is Less By 54 From Old Number So,

==> 31X - 54 = 13X

==> 31X - 13X = 54

==> 18X = 54

==> X = 54/18

==> X = 3

hEnCe tHe rEqUiReD nUmBeR iS,

( 10 × 3 × 3 ) + 3

= ( 30 × 3 ) + 3

= 90 + 3

= 93