the digit in the tens place of a two digit number is three times that in the unit place. if the digit are reversed, the new number will be 36 less than the original number. find the original number. check your solution
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Answered by
1
Let the one's digit be y and tens digit be x,
Number = 10x + y
Then,x=3y⋯(i)
Reversed number = 10y + x
A.t.Q :- (10x+y)−(10y+x)=36 Put x = 3y in eq. (i)
⇒9x−9y=36
⇒x−y=4⋯(ii)
⇒3y−y=4
∴2y=4 x=3y ∴x=6
y=2
∴ Number = 62
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Answered by
0
Answer:
number is 93 because 93 when reversed it is 39 and when subtracted 39 from 93 we get 36
Step-by-step explanation:
this can be done by trail and error method
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