Question

the digit in the tens places of a two digit number is 6 more than the digit in the units places sum of the number and he number obtain by reversingthe digit is 66.

Answer 1

Answer:

the required number is 60

Step-by-step explanation:

let the number in 10s place is x

let the number in unit place is y

x is 6 more than y

x = y + 6

x - y = 6 equ (1)

the two digits number will be 10x + y

sum of two digits number and it's reverse is 66

10x + y + 10y + x = 66

11x + 11y = 66

11(x + y) = 66

x + y = 6 equ (2)

adding (1) & (2) we get

2x = 12

x = 12/2 = 6

substitute x in equation (2)

x + y = 6

6 + y = 6

y = 6 - 6

y = 0

the required number is

= 10x + y

= 10(6) + 0

= 60