Question

the digit in the tenth place of a two number digit number is 3 less than the digit in its units place. Find the number if quotient
obtained when the number is divided by the sum of its digits is 4.​

Answer 1

Answer:

ANSWER=36

Step-by-step explanation:

ONES PLACE = X :TENS PLACE=X-3

NUMBER=10(X-3)+X=11X-30

GIVEN: 11X-30/ (X+3)= 4

11X-30=4(X+3)

11X-30=4X+12

7X=42

X=6

NUMBER=10(3)+6=36