Question

The digit in the tenths place of two digit number is three times that in ones place. If the digits are reversed, the new number will be 36 less than the original number. Find the original number.​

Answer 1

Answer: Number=62

Step-by-step explanation:

Let the one's digit be y and tens digit be x,

Number = 10x + y

Then,x=3y⋯(i)  

Reversed number = 10y + x  

A.t.Q :- (10x+y)−(10y+x)=36 Put x = 3y in eq. (i)

⇒9x−9y=36

⇒x−y=4⋯(ii)

⇒3y−y=4

∴2y=4  x=3y  ∴x=6

y=2

∴ Number = 62