the digit in the unit place of a two digit number is 4 times the digits in the tens place the number obtained by reversing the number by 54 find the number
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Answer:
Let one's digit be 4x. Then, ten's digit =x.
Number =10x+4x=14x ....(1)
Number obtained by reversing the digits =40x+x=41x
According to the given condition,
41x−14x=54
27x=54
x=2
Putting the value of x in (1) , we get
Number =14×2=28
Hence, 28 is the required number.
OR
According to question, if the digits are reversed and the original number is subtracted from the new number, the difference is 54. Hence the desired number is 14a = 14(2) = 28 Required number is 28.
I hope it was right answer !!
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