Question

the digit in the unit place of a two digit number is equal to the digit in the tens place of one- third of number and the digit in the tens place of the original number is 2 less than the digit in the units place of one- third of the number. if the sum of the digits of the original number is 6 , then what is the number?

A . 15

B. 24

C. 42

D. 51

E. 33​

Answer 1

Answer:

two digit number=10x+y

when its divides by answer will be 10y+(x+2)

(as told in the question)

x+ y =6

so, the numbers are x,6-x

$\frac{10x +( 6 - x)}{3} = 10(6 - x) + (x + 2) \\ \\ 10x + 6 - x = 3 \times(( 60 - 10x) + x + 2) \\ 10x + 6 - x = 180 - 30x + 3x + 6 \\ 10x = 180 - 30x + 3x + 6 - 6 +x \\ 10x = 180 - 30x + 4x \\ 10x = 180 - 26x \\ 10x + 26x = 180 \\ 36x = 180 \\ x = \frac{180}{36} \\ \\ x = 5$

x=5 ,

6-x

=6-5=1,

so,

the number is 10x+(6-x)

=51

answer is 51

hope this will help u...

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