Question

The digit in the units place of a two digit number is divided by the sum of its digits is 4. Find the number.

Who will give a correct answer with complete method, I will mark them as brainlist. ​

Answer 1

Let the digits be x and let the units digits be y

Then, the required number is 10x+y

According to the question sum of digits =x+y

x+y10x+y=8

⇒10x+y=8x+8y

⇒10x−8y=8y−y

⇒2x=7y

⇒2x−7y=0−−−−−−−−−−(1)

Given,

x−3y=1−−−−−−−−−−−−−(2)

from equation (1) and (2)

2x−7y=0

(x−3y=1)×2

2x−7y=02x−6y=2− + −−−−−−−−−  −y=−2

y=2

put in equation (1)

2x−7y=0

2x−×2=0

2x=14

x=7

Hence the number is 10x+y

⇒ 10×7+2

=72

Hence, this is the answer.

Please mark me the brainliest