Question

The digit in the units place of a two digit number is 8 more than the digit in the tens place. Let the digit at units place be x. Then the numbe is​

Answer 1

Answer:

Correct option is  

71

In the two digit number, let the digit in the units place is x and the digit in the tens place is 7.

∴ The number is 10(7)+x=70+x

Sum of digits =8 times the digit in the units place.

∴ Sum of both the digits =8× digit at units place

∴7+x=8×x

∴7=7x

∴x=1

Now, substituting x=1 in required number 70+x, we get

70+x=70+1=71

Explanation:

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Answer 2

Answer:

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