Question

the digit in units place of the number 17^1999+11^1999-7^1999 is :

Answer 1

the digit in unit place of the number is 1

Answer 2

Answer:   1

Step-by-step explanation:

we know that to find unit digit of any number which have a bigger power we factorize in that power into 4n so that we can calculate unit digit.

in $17^{1999}$

we calculate only $7^{1999}$

= $(7^{4}) ^{499}$

unit digit = 1

same unit digit in $7^{1999}$

and in $11^{1999}$

unit digit is 1 because 1 to the power anything will be unit digit 1

so unit digit of whole expression

= 1 + 1 -1

= 1

so unit digit will be 1