the digit of 2 digit number differ by 3 if the digits are interchanged and resulting the number is added to original number we get 121 find the original number
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The digits of a 2 digit number differ by 3, if the digits are interchanged and the resulting number is added to the original number we get 121.
Let the digits of the number be a and b such that the number is (10a+b).
According to the question,
➭ a − b = 3 ...... (1)
➭ 10a + b + 10b + a = 121
➭ 11a + 11b = 121
➭ a + b = 11 ...... (2)
Add (1) and (2) , we get
➭ a - b + a + b = 3 + 11
➭ 2a = 14
➭ a = 7
Substitute a = 7 in equation 2 , we get
➭ 7 + b = 11
➭ b = 11 - 7
➭ b = 4
Now, we have to find the numbers
➭ 10a + b
➭ 10(7) + 4
➭ 70 + 4
➭ 74
Hence Verified
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