Math, asked by sandeepkumar43833, 5 months ago

the digit of a 2 digit number differ by 5 if the digit are interchanged andthe resulting number is added to the orignal number we get 99 find the orignal number​

Answers

Answered by Anonymous
2

Answer:

Let the one digit number be x

And tens digit number be y

(y>x)

No. 10y+x

And interchanged no. =10x+y

According to the question,

x-y=5.............¡

10y+x+10x+y=99

=>11y+11x=99

=>x+y=9..........¡¡

Now ¡¡-¡ we get,

x+y-(x-y) =9-5

=>2y=4

=>y=2

Putting y=2in equation ¡

x-y=5

=>x-2=5

=>x=7

The number is

10y+x=10×2+7=27

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Answered by vankarkalpanaben2874
0

Answer:

The number is

10y+=10x2+7

=27

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