the digit of a positive integer having three digit are in ap and their sum is 15 the number obtained by reversing the digit is 594 less than yhe original number find the number
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Let the three digit number is abc
a+b+c=15
cba=abc-594
100c+10b+a=100a+10b+c-594
99a=594+99c
a=6+c
6+c+b+c=15
2c+b=9
So solve the equations for the values of abc
a+b+c=15
cba=abc-594
100c+10b+a=100a+10b+c-594
99a=594+99c
a=6+c
6+c+b+c=15
2c+b=9
So solve the equations for the values of abc
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