Question

the digit of a positive number of three digit are in AP and their sum in 15 . the number obtained by reversing the digit is 595 less than the original number find the number​

Answer 1

let the original three-digit number be xyz .

since digits x,y and z are in AP (given)

therefore,

let x = a - d 

     y = a

     z = a + d

(where a and d are the first term and common difference respectively.)

now, according to the question,

x + y + z = 15

a - d +a + a + d = 15

3a = 15

a = 5

So , a = 5 ----- ( 1 )

Also, another condition given is

zyx = xyz - 594

100.z + 10.y + x = 100.x + 10.y + z - 594

100( a + d ) + 10( a ) + ( a - d ) = 100( a - d ) + 10( a ) + ( a + d ) - 594

on further solving the above equation, we get

d = - 3 ----- (2)

NOW,

x = a - d = 5 - (-3) = 8                           (from 1 and 2)

y = a = 5                                               (from 1)

z = a + d = 5 + (-3) = 2                          (from 1 and 2)

Thus, the required number is 852.

Answer 2

Answer:-

The given number 1975 could be the hospital room number or postal code where she was born.

Explanation :-

Given :

A women born in 1975 and died in 1975 at the age of 22 yrs.

But how ?

In the given question, it is not mentioned that the given number 1975 is an year.

So, It could be the hospital room number where she was born and then died at same(1975) room number in some hotel.

It could be the postal code of the area where she was born and died in the same place at the age 22 years.