Question

The digit of a positive number of three digits are in ap and their sum is 15 the number obtained by reversing the digits is 594 less than the original number find the number

Answer 1

Answer:

The number is 852. The number obtained by reversing is 258

Step-by-step explanation:

Let the three digits of the numbers be a1, a2,a3.

a+a+d+a+2d=15

3a+3d= 15

a + d= 5

a2=5

a1=5-d

a3=5+d

[100a1+10a2 +a3]-[100a3+10a2+a1] = 594

[500-100d +50+5+d] - [500+100d + 50 +5-d=594.

[555-99d] - [555 +99 d]=594

555-99d-555-99d = 594

-198d=594

d= 594/-198

d = -3

a1= 5-(-3)

=8

a3= 5+ (-3)

=2.

The number is 852. The number obtained by reversing is 258