Question

the digit of a three digit positive number are in AP and the sum of digit is 15 on subtracting 594 from the number the digits are interchanged find the number​

Answer 1

Answer:

852

Step-by-step explanation:

let a, b and c be the digits in hundreds place, tens place and once place respectively.

sum=15

But sum will be 3 times the middle term.

∴ b=5

original number is 100a+10b+c and the number reversed is 100c+10b+a

So 100a+10b+c-594=100c+10b+a

99(a-c)=594

a-c=6

b=5, a-c=6 and a,b and c are in ap implies that a=8, b=5, and c=2

Therefore, the number is 852