Question

the digit of a two digit number differ by 18 the digit interchange and the resulting number is added to the original number we get 99 find the original number

Answer 1

Answer:

Hey

Here is your answer

Let the digit at ones place be x

It is given that the sum of the digits of the number is 18

The digits at tens place =18-x

Thus,the original number =10×(18-x)+x

=180-18x+x

=120-9x

New number =10x +(18-x)

=9x+18

It is given that the new number added the original number by 99

I. E new number - original number =99

(9x+18)-(120-9x)=99

Or 9x+18-120+9x=99

18x-102=99

18x=99+102

18x=201

Or 201/18

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