The digit of a two digit number differ by 3 if the digits are interchanged and the resulting number is added to the original number, we get 143. What can be the original number ?
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Answers
Answered by
3
x+x+3=143
2x=143-3
x=140/2
x=70
Answered by
5
Solution :-
Let the digit in ones place be x.
So, the digit in tens place be x + 3.
Original no. = 10(x + 3) + 1(x)
= 10x + 30 + x
= 11x + 30
New no. = 10(x) + 1(x + 3)
= 10x + x + 3
= 11x + 3
According to Question,
Original no. + New no. = 143
(11x + 30) + (11x + 3) = 143
⇒ 22x + 33 = 143
⇒ 22x = 143 - 33
⇒ 22x = 110
⇒ x = 110 / 22
⇒ x = 5
Required Numbers –
Original no. = 11x + 30
= 11(5) + 30
= 55 + 30
= 85
New no. = 58
Hence, the required number is 58.
Hope It Helps !!!
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