Math, asked by Stylishhh, 1 year ago

The digit of a two digit number differ by 3 if the digits are interchanged and the resulting number is added to the original number, we get 143. What can be the original number ?​


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Answers

Answered by ayush939194
3

x+x+3=143

2x=143-3

x=140/2

x=70


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Answered by Stylishboyyyyyyy
5

Solution :-

Let the digit in ones place be x.

So, the digit in tens place be x + 3.

Original no. = 10(x + 3) + 1(x)

= 10x + 30 + x

= 11x + 30

New no. = 10(x) + 1(x + 3)

= 10x + x + 3

= 11x + 3

According to Question,

Original no. + New no. = 143

(11x + 30) + (11x + 3) = 143

⇒ 22x + 33 = 143

⇒ 22x = 143 - 33

⇒ 22x = 110

⇒ x = 110 / 22

x = 5

Required Numbers

Original no. = 11x + 30

= 11(5) + 30

= 55 + 30

= 85

New no. = 58

Hence, the required number is 58.

Hope It Helps !!!


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