The digit of a two digit number differ by 5 . if thr digit are reversed , the sum of the two numbers is 99. find the numbers ??
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Let us assume, x and y are the two digits of a two-digit number.
Therefore,
The number = 10x + y and when the digits are reversed, the number = 10y + x
Given:
x - y = 5 ------------1
Also given:
10x + y + 10y + x = 99
11x + 11y = 99
x + y = 9 -------------2
Adding equation 1 and equation 2
2x = 14
x = 7
Therefore, y = x - 5 = 7 - 5 = 2
The number is = 10x + y = 10 * 7 + 2 = 72
And the reversed number = 10y + x = 10 * 2 + 7 = 27
Therefore,
The number = 10x + y and when the digits are reversed, the number = 10y + x
Given:
x - y = 5 ------------1
Also given:
10x + y + 10y + x = 99
11x + 11y = 99
x + y = 9 -------------2
Adding equation 1 and equation 2
2x = 14
x = 7
Therefore, y = x - 5 = 7 - 5 = 2
The number is = 10x + y = 10 * 7 + 2 = 72
And the reversed number = 10y + x = 10 * 2 + 7 = 27
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