Math, asked by bhavagnya2421, 11 hours ago

The digit of two-digit number differ by 3. If digits are interchanged, and the resulting number is added to the original number, we get 121. Find the original number. ​

Answers

Answered by varadad25
33

Answer:

The original number is 74.

Step-by-step-explanation:

Let the greater digit at tens place be x.

And the smaller digit at units place be y.

∴ Two-digit number = xy

Original number = 10x + y

From the first condition,

The digits of the original number differ by 3.

x - y = 3

⇒ x = 3 + y

x = y + 3 - - - ( 1 )

Now,

The number obtained by interchanging digits = yx

New number = 10y + x

From the second condition,

Original number + New number = 121

⇒ 10x + y + 10y + x = 121

⇒ 10x + x + y + 10y = 121

⇒ 11x + 11y = 121

⇒ x + y = 11 - - - [ Dividing each term by 11 ]

⇒ ( y + 3 ) + y = 11 - - - [ From ( 1 ) ]

⇒ y + 3 + y = 11

⇒ y + y = 11 - 3

⇒ 2y = 8

⇒ y = 8 ÷ 2

y = 4

By substituting y = 2 in equation ( 1 ), we get,

x = y + 3 - - - ( 1 )

⇒ x = 4 + 3

x = 7

Now,

Original number = 10x + y

⇒ Original number = 10 * 7 + 4

⇒ Original number = 70 + 4

Original number = 74

∴ The original number is 74.

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