Question

The digit of two digit number differ by 3.if the digit are interchanged,

and resulting number is add up to the original number, we get 143. What

can be the original number?​

Answer 1

Answer:

58 or 59

Step-by-step explanation:

let us all consider the tens digit number of the original number as 10x and the ones digit number as x .

so ,here we can see as we read above that these two digits differ by 3 which means 10x-x (or you can say that 11x as)=3

we can take that as (i am saying about the 3 ) -3 .So as we know that once a number is transposed from LHS TO RHS OR RHS TO LHS we obtain the opposite of the operator given to the number if take an example the result -3 which we have got in this equation is said to be +3 when we transpose

so guys we obtain ,10x+(x+3)

so these italicised words are soooo important

let the newly formed interchanged number be 10(x+3)+x

so

here

10x+(x+3) +10(x+3)+x gives 143

11x+3+10x+30+x gives 143

here

22x+33 gives 143

by transposing the 33

we obtain

143-33=22x

110=22x

therefore

x=5

so the original number is

10x+x+3

50+5+3

which is 58

it could be 85 also

Answer 2

I solve this question.You can see in the above pictures.

If you have any doubt in this question please comment

I hope this help.you