Question

The digital in the tens place of a two digit number is three times that in the units place if the digits are reversed the new number will be 36 less than the original number find the original number
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Answer 1

Answer:

The required original number is 62.

Step-by-step explanation:

Consider the provided information.

The digit in the tens place of a two digit number is three times that in the units place, and If the digits are reversed the new number will be 36 less than the original number.

And, we need to find out the original number.

Let us assume that, the units place be $x.$

As it is given that, The digit in the tens place of a two digit number is three times that in the units place, so the digit in tens place will be $3x.$

The number is $3x + x.$

Now,

$\implies 10x + 3x = 30x + x - 36$

$\implies 13x = 30x + x - 36$

$\implies 13x = 31x - 36$

$\implies 13x - 31x = - 36$

$\implies - 18x = - 36$

$\implies 18x = 36$

$\implies x = \dfrac{36}{18}$

$\implies x = 2$

Therefore,

• The original number, 31x = 31 × 2 = 62.

Hence, the required original number is 62.

#Learn more:

The ration of two number is 3: 5. if both numbers are increased by 5 their ratio becomes 2:3 find the number.

brainly.in/question/32477953

Answer 2

Answer:

Given :-

• The digits in the tens place of a two digit number is three times that in the units place.
• The digits are reversed the new will be 36 less than the original number.

To Find :-

• What is the original number.

Solution :-

Let,

$\mapsto$ The digits in the one's place be x

$\mapsto$ The digits in the ten's place will be 3x

Hence,

$\dashrightarrow$ The original number will be :

$\implies \sf 10 \times 3x + x$

$\implies \sf 30x + x$

$\implies \sf\bold{\purple{31x}}$

According to the question :

$\implies \sf 30 + x - 36 =\: 10x + 3x$

$\implies \sf 31x - 36 =\: 13x$

$\implies \sf - 36 =\: 13x - 31x$

$\implies \sf \cancel{-} 36 =\: \cancel{-} 18x$

$\implies \sf \dfrac{\cancel{36}}{\cancel{18}} =\: x$

$\implies \sf 2 =\: x$

$\implies \sf\bold{\purple{x =\: 2}}$

Hence, the required original number is :

$\leadsto \sf 31x$

$\leadsto \sf 31(2)$

$\leadsto \sf 31 \times 2$

$\leadsto\bold{\red{62}}$

$\therefore$ The original number is 62.