Question

the digits at tens place of a digit of a two digit number is two times the digit at ones place.if digits are reversed the number becomes 18 less than the original number.what is the original number​

Answer 1

Step-by-step explanation:

hey mate

here is your answer

____________________

Number is 62.

Let say ‘x' is digit on one's place so 3x is digit on tens' place

So number is 10*3x+x=31x

Now if reverse the possition of digit new number is

10*x+3x=13x

As given new number is less by 36 from old number

31x-36=13x

18x=36

x=2

So number is 10*3*2+2=62.

plz mark my answer as brainliest if it helps

:)

Answer 2

Answer:-

$20x + x = 21x$

$(10x+2x =12x)$

Hence,

$(21x - 12x = 18)$

$(9x =18 ) \\ </p><p>(x =18÷9) \\ </p><p>(x =2 )$Therefore, Original number =

(2×21) ``42

Answer=42