The digits at the tens place of a two digit number is three times the digit at ones place . If the sum of the number and the new number formed by reversing the digits is 88. find the original number.
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let the digit in one's place be x. the original number= 10(3x) + x (we multiplied by 10 because we have to find the value in ten's place.) so the required number is 62.
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