Question

the digits.
How many times does the digit 5 occur in tens place in the numbers between 100 and 500?

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Answer 1

Answer:

Answer is four times.

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Answer 2

5 occur 79 times in tens place in the numbers between 100 and 500.

Explanation:

First term = 105

Common difference = 5

Last term = 495

nth term = a + (n - 1)d

495 = 105 + (n - 1)5

495 - 105 = 5(n - 1)

390 = 5(n - 1)

390/5 = n - 1

78= n - 1

78+ 1 = n

79 = n

Hence, 5 occur 79 times in tens place in the numbers between 100 and 500.

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