Question

The digits in a 3 digit number are in A.P. Their sum is 15. It the digits are
interchanged, the new number obtained is 594 less than the original number.
Find the three digit number​

Answer 1

Let the hundred's, ten's and unit digit's be a+d,a,a−d

Then, a+d+a+a−d=15

⇒3a=15⇒a=5

[100(a+d)+10a+(a−d)]−[100(a−d)+10a+(a+d)]=594

⇒99d+99d=594⇒198d=594⇒d=3

Hence, the requried number is 852.


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