The digits od a two-digit number differ by 3. if digits are interchanged and the resulting number is added to the original number, we get 121. find the original number.
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Let the original number be 10x + y, then x-y = 3
=> x= 3+y
A.T.P.
(10x+y)+(10y+x)=121
=>10(3+y)+y+10y+(3+y)=121
=>30+10y+11y+3+y=121
=>22y+33=121
=>22y=88
=>y=4
x=3+4=7
The original number=74
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