The digits of a 2 digit no. differ by 3. If the digits are interchanged and the resulting no. is added to the orignal no. wee get 99. What can be the orignal no....
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Let us assume, x and y are the two digits of the two-digit number and x > y
Therefore, the two-digit number = 10x + y and reversed number = 10y + x
Given:
x - y = 3 ------------1
Also given:
10y + x + 10x + y = 99
11x + 11y = 99
x + y = 9 --------------2
Adding equation 1 and equation 2
2x = 12
x = 6
Therefore, y = x - 3 = 6 - 3 = 3
Therefore, the two-digit number = 10x + y = 10*6 + 3 = 63
The original two-digit number = 63
Therefore, the two-digit number = 10x + y and reversed number = 10y + x
Given:
x - y = 3 ------------1
Also given:
10y + x + 10x + y = 99
11x + 11y = 99
x + y = 9 --------------2
Adding equation 1 and equation 2
2x = 12
x = 6
Therefore, y = x - 3 = 6 - 3 = 3
Therefore, the two-digit number = 10x + y = 10*6 + 3 = 63
The original two-digit number = 63
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