Question

the digits of a 2 digit no differ by 3 if the digits are interchange and the resulting no is added to the original no we get 143

Answer 1

Hey there!!

Let the ten's digit of the original number be x,

And, the unit's digit of the original number be y .

Now, A/Q

∵ x - y = 3 ............(1).

Original number = 10x + y .

Number obtained on interchanging the digits = 10y + x .

A/Q,

⇒ 10x + y + 10y + x = 143.

⇒ 11x + 11y = 143 .

⇒ 11( x + y ) = 143 .

⇒ x + y = 143/11.

∵ x + y = 13.............(2).

On substracting equation (1) and ( 2 ), we get

x - y = 3 .

x + y = 13 .

-   -      -

_________

⇒ -2y = -10 .

⇒ y = -10/-2 .

∴ y = 5 .

On putting the value of y in equation (1), we get

∵ x - y = 3 .

⇒ x - 5 = 3 .

⇒ x = 3 + 5 .

∴ x = 8 .

∵ Original number = 10x + y .

= 10 × 8 + 5 .

= 80 + 5 .

= 85 .

Hence, the original number is 85 .

THANKS

#BeBrainly.

Answer 2

$(text) \large{dear friend}$
here is your solution OK........... ☺☺☺☺


it's question depend on hit and try

Let the number be 10x+y.

x-y = 3 …(1)

10x+y+10y+x = 143

11x + 11y = 143, or

x+y = 13 …(2)

Add (1) and (2)

2x = 16, or

x = 8 so y = 5.

Check 85+58 = 143. Correct.

The number is 85.