the digits of a 2-digit no. differ by 5 . If the digits are interchanged and the resulting number is added to the original number, we get 99. Find the original number
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Answer:
Let the number be 10x + y
Given,
x-y=5
10x+y+10y+x=99
To find,
10x+y
Solution,
11x+11y=99
11(x+y)=99
x+y=9
x+y=9
x-y=5
2x=14
x=7
x-y=5
7-y=5
y=2
∴10x+y=70+2=72
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