Question

the digits of a 2 digit number differ by 3 if the digits are interchanged and the two numbers are added their sum is 77 find the numbers

Answer 1

Answer:

Here is your answer

Let the digit at units place be x

Let the digit at tens place be x + 3

10(x + 3) + x

When digits interchanged, the number becomes 10x + x + 3

According to the question,

10(x + 3) + x + 10x + x + 3 = 77

10x + 30 + 12x + 3 = 77

22x + 33 = 77

22x = 77 - 33

22x = 44

x =  

x = 2

∴ The number = 10(x + 3) + x = 10 * 5 + 3 + 5 = 50 + 3 + 5 = 53 + 5 = 58

∴ The number is 58